0.64x^2+1.6x+1=0

Solution for 0.64x^2+1.6x+1=0 equation:

0.64x^2+1.6x+1=0

a = 0.64; b = 1.6; c = +1;
Δ = b2-4ac
Δ = 1.62-4·0.64·1
Δ = 4.4408920985E-16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.6)-\sqrt{4.4408920985E-16}}{2*0.64}=\frac{-1.6-\sqrt{4.4408920985E-16}}{1.28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.6)+\sqrt{4.4408920985E-16}}{2*0.64}=\frac{-1.6+\sqrt{4.4408920985E-16}}{1.28}
$